Answer:
[tex]T_c=-210.15^{\circ}C[/tex]
Explanation:
In this question we need to convert the temperature in kelvin to degree Celsius. The conversion from kelvin scale to Celsius scale is as follows :
[tex]T_k=T_c+273.15[/tex]
Here,
[tex]T_k=63\ K[/tex]
[tex]T_k-273.15=T_c[/tex]
[tex]63-273.15=T_c[/tex]
[tex]T_c=-210.15^{\circ}C[/tex]
Here, negative sign shows that the heat is released. So, the temperature at 63 K is equivalent to 210.15 °C. Hence, this is the required solution.
