kayla3003 kayla3003

01-11-2019
Mathematics

contestada

Solve for all possible values of x.
VX-9+4= 8

Respuesta :

a5904640 a5904640

01-11-2019

[tex]\sqrt{x-9}+4=8[/tex]

[tex]\sqrt{x-9}=8-4[/tex]

[tex]\sqrt{x-9}=4[/tex]

Put ^2 in both sides

[tex]\sqrt{x-9}^2=4^2[/tex]

[tex]x-9=16[/tex]

[tex]x=16+9[/tex]

[tex]x=25[/tex]

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