To find the x-intercept we need to substitute y = 0 into the equation of the line and solve for x, as follows:
[tex]\begin{gathered} 3x+0=15 \\ 3x=15 \\ \frac{3x}{3}=\frac{15}{3} \\ x=5 \end{gathered}[/tex]Then, the x-intercept is the point (5, 0)
To find the y-intercept we need to substitute x = 0 into the equation of the line and solve for y, as follows:
[tex]\begin{gathered} 3(0)+y=15 \\ y=15 \end{gathered}[/tex]Then, the y-intercept is the point (0, 15)
