Explanation:
We would be applying the trigonometry identity that shows thr=e relationship between tanθ and secθ:
[tex]\sec ^2\theta=tan^2\theta\text{ + 1}[/tex]
we make tanθ the subject of formula:
[tex]\begin{gathered} \text{subtract 1 from both sides:} \\ \sec ^2\theta-1=tan^2\theta\text{ + 1}-1 \\ \sec ^2\theta-1=tan^2\theta\text{ } \\ \text{square root both sides:} \\ \sqrt[]{\sec ^2\theta-1)}\text{ =}\sqrt[]{tan^2\theta\text{ }} \end{gathered}[/tex]
