ShantelC621837 ShantelC621837
  • 03-11-2022
  • Mathematics
contestada

Problem 12a) solve for x, 3(-2x +5) = 9(x-5), x=b) x = –27, x =

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AirrionB101319 AirrionB101319
  • 03-11-2022

The given equation is

[tex]3(-2x+5)=9(x-5)[/tex]

Dividing by 3 both sides, we get

[tex]\frac{3\mleft(-2x+5\mright)}{3}=\frac{9\mleft(x-5\mright)}{3}[/tex]

[tex]-2x+5=3(x-5)[/tex]

Multiplying 3 and (x-5) as follows.

[tex]-2x+5=3\times x-3\times5[/tex]

[tex]-2x+5=3x-15[/tex]

Adding 15 on both sides, we get

[tex]-2x+5+15=3x-15+15[/tex]

[tex]-2x+20=3x[/tex]

Adding 2x on both sides, we get

[tex]-2x+20+2x=3x+2x[/tex]

[tex]20=5x[/tex]

Dividing by 5, we get

[tex]\frac{20}{5}=\frac{5x}{5}[/tex][tex]4=x[/tex]

Hence the value of x is 4.

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