VeraQ522139 VeraQ522139
  • 03-11-2022
  • Mathematics
contestada

I need HELP PLS!!! ITS HARD TO DO I NEED HELP

I need HELP PLS ITS HARD TO DO I NEED HELP class=

Respuesta :

BakaryF142876 BakaryF142876
  • 03-11-2022

ANSWER:

B.

[tex]x^{\frac{7}{6}}[/tex]

STEP-BY-STEP EXPLANATION:

We have the following expression:

[tex]\mleft(\sqrt{x}\mright)\mleft(\sqrt[3]{x^2}\mright)[/tex]

We simplify and we have:

[tex]\begin{gathered} (\sqrt[]{x})=x^{\frac{1}{2}} \\ (\sqrt[3]{x^2})=x^{\frac{2}{3}} \\ \text{therefore:} \\ x^{\frac{1}{2}}\cdot x^{\frac{2}{3}}=x^{\frac{1}{2}+\frac{2}{3}} \\ \frac{1}{2}+\frac{2}{3}=\frac{1\cdot3+2\cdot2}{2\cdot3}=\frac{3+4}{6}=\frac{7}{6} \\ x^{\frac{7}{6}} \end{gathered}[/tex]

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