jacyliles343 jacyliles343
  • 03-09-2017
  • Mathematics
contestada

The product of two consecutive even integers is 288 find the integers.

Respuesta :

quenbarr quenbarr
  • 13-09-2017
using algebra
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18
this is another solution
as you can see, it's just a matter of factoring 288using arithmetic...√288=16.97≈1716 and 18 are the integers (as well as -16 and -18)
Answer Link

Otras preguntas

What is your favorite science subject?​
Which of these is a socialist aspect of the American mixed economy? A) Consumers can decide to buy wind energy from a power company. B) Education through high s
Sally spends 90% of her weekly income on rent. If her rent is $720 each week, find her weekly income.
Help meeeeeeeeee!!!!!!!!!
HELP! this is due today
How do I say Mathematics in Spanish?
What kind of questions do biologists attempt to answer?
What is the density of a silver coin from the following data:Mass of silver coin 6.581 gVolume of coin and water 23.7 mLVolume of water alone 23.1 mLThe answer
When x = 3, x² + 3(x + y) = ?​
Which of the following transformations will produce similar figures? Select all that apply. (-x, y) (x + 2, y - 5) (2x, 4y) ( 1/2x,1/2 y)