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The rectangle shown has a perimeter of 62 cm and the given area. its length is 4 more than twice its width. write and solve a system of equations to find the dimensions of the rectangle.

Respuesta :

what is the area?

taking the length to be 2x+4 and the width to be x,

[tex]62 = 2(2x + 4 + x)[/tex]
hence,
[tex]6x = 54[/tex]
and thus
[tex]x = 9[/tex]


that means the width is 9.
since we established that the length is (2x+4), we can substitute x=9 into the equation. hence,
[tex]2x + 4 = 2(9) + 4 = 22[/tex]
therefore the length is 22

use the area to check your answer!

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