jennifergray11 jennifergray11
  • 04-05-2018
  • Mathematics
contestada

Evaluate log38, given log32 ≈ 0.631.

Respuesta :

gmany
gmany gmany
  • 04-05-2018
[tex]\log_38-\log_32^3=3\log_32\approx3\cdot0.631=1.893\\\\Used:\log_ab^n=n\cdot\log_ab[/tex]
Answer Link
lisboa lisboa
  • 25-01-2019

Answer:

1.893

Step-by-step explanation:

[tex]log_3(8)[/tex]

first we write 8 in exponential form

8=2*2*2= 2*3

[tex]log_3(2^3)[/tex]

Now we apply log property

[tex]log_b(a^n)= n log_b(a)[/tex]

As per this property we move the exponent before log

[tex]log_3(2^3)= 3 log_3(2)[/tex]

Given log_3(2) = 0.631

Plug in the value

[tex]log_3(2^3)= 3 log_3(2)= 3*0.631= 1.893[/tex]

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